Question

What is the molarity of a solution made by dissolving 5.5 g of KI in enough water to make 150 ml of solution?

Answer 1

Step-by-step explanation:

molarity is moles of solute/L solution

5.5 g 1 moles Kl 1000 mL

_____ * __________ * ________ = 0.22088 M

150 ml of solution 166 grams 1 L

(39 grams K+ 127 grams I) ^

Answer 2

`\boxed{\text{0.22 mol/L}}`

Step-by-step explanation:

`\text{Molar concentration} = \frac{\text{moles}}{\text{litres}}\\\\\text{c} = (n)/(V)`

1. Convert grams to moles.

`\text{Moles KI = 5.5 g KI} * \frac{\text{1 mol KI}}{\text{166.0 g KI}} = \text{0.0331 mol KI}`

2. Convert millilitres to litres

`\text{V = 150 mL} * \frac{\text{1 L}}{\text{1000 mL}} = \text{0.1500 L}`

3. Calculate the molar concentration

`c = \frac{\text{0.0331 mol}}{\text{0.1500 L}} = \text{0.22 mol/L}`

The molar concentration of KI is
`\boxed{\textbf{0.22 mol/L}}`.