Question

An air-track glider attached to a spring oscillates between the 15.0 cm mark and the 68.0 cm mark on the track. The glider completes 7.00 oscillations in 31.0 s . What is the period of the oscillations?

Answer 1

4.42 s

Step-by-step explanation:

The frequency of the oscillation is given by the ratio between the number of complete oscillations and the time taken:

`f=(N)/(t)`

where for this glider, we have

N = 7.00

t = 31.0 s

Substituting, we find

`f=(7.00)/(31.0 s)=0.226 Hz`

Now we now that the period of oscillation is the reciprocal of the frequency:

`T=(1)/(f)`

So, substituting f = 0.226 Hz, we find:

`T=(1)/(0.226 Hz)=4.42 s`