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Evaluate the integral by finding parametric equations for the line segment from ​(4​,4​,2​) to ​(5​,8​,negative 4​) and evaluating the line integral of fequalsyiplusxjplus3k along the segment.

User Supita
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1 Answer

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Parameterize the line segment (call it
C) by


\vec r(t)=(1-t)(4,4,2)+t(5,8,-4)=(4+t,4+4t,2-6t)

with
0\le t\le1. Then the line integral of
\vec f(x,y)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k is


\displaystyle\int_C\vec f\cdot\mathrm d\vec r=\int_0^1(4+4t,4+t,3)\cdot(1,4,-6)\,\mathrm dt=\int_0^1(2+8t)\,\mathrm dt=6

User Raulmarcosl
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