Answer: Obtion B
![P = 1.3e ^ {-0.038t}\\\\P = 2.1e ^ {-0.046t}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n7vlxhbzandb85thvtbh6r18xxnuct95vt.png)
Explanation:
The equation for exponential decay has the following form:
![y = pe ^(-rt)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wm5kuksx0v8u4tfwa1rwkqwps7rclm6abr.png)
Where
p is the initial population
r is the rate of decrease
t is time.
In this problem we have to:
The current population of insect A to be 1.3 million and the current population of insect B to be 2.1 million.
So
in millions
in millions
We also need the populations of insect to be reduced at a rate of 3.8% and insect to be reduced at a rate of 4.6%.
so:
![r_1 = 0.038\\\\r_2 = 0.046](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n4tc18z4i5noto6el5ptyrhunu1g6w34ia.png)
then the exponential decay equation for insect A is:
![P = 1.3e ^ {-0.038t}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q6f7v02h9p2jdgpflnzauq8v8reghrllzl.png)
the exponential decay equation for insect B is:
![P = 2.1e ^ {-0.046t}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qkgrp8q9ywpenirz3lfsyjy53zlluy5p7m.png)
Finally, the system of equations is:
![P = 1.3e ^ {-0.038t}\\\\P = 2.1e ^ {-0.046t}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n7vlxhbzandb85thvtbh6r18xxnuct95vt.png)
The answer is the Option B