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Angles of elevation and depression-SOMEONE HELP ME

Angles of elevation and depression-SOMEONE HELP ME-example-1

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If the angle of depression is 28° the complementary angle in the triangle is 62°. With this you can use soh-cah-toa to find the x value.

cos62 = 350/x; multiply both sides by x

cos62 x = 350; divide both sides by cos62

x = 350 / cos62

x = 745.519

x = 746 ft

Hope this helps you!

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