Question

URGENT PLEASE HELP 98 POINTS Find the direction angle of vector v to the nearest tenth of a degree.

Answer 1

The direction angle of vector v is equal to 9.5\°

Explanation:

Let

A(-5,0),B(7,2)

The vector v is given by

v=B-A

v=(7, 2) - (-5, 0)

v=((7 - (- 5)), (2-0))

v=(12, 2)

Remember that

The direction angle of the vector is equal to

tan (\theta) =\frac{y}{x}

substitute the values

tan (\theta) =\frac{2}{12}

\theta=arctan(\frac{2}{12})=9.5\°

Explanation:

put that in a computer calc and it shoud give u the awnser

Answer 2

The direction angle of vector v is equal to
`9.5\°`

Explanation:

Let

`A(-5,0),B(7,2)`

The vector v is given by

`v=B-A`

`v=(7, 2) - (-5, 0)`

`v=((7 - (- 5)), (2-0))`

`v=(12, 2)`

Remember that

The direction angle of the vector is equal to

`tan (\theta) =(y)/(x)`

substitute the values

`tan (\theta) =(2)/(12)`

`\theta=arctan((2)/(12))=9.5\°`