Answer:
Observe the attached image
Explanation:
We have the graph of a line that passes through the points (0,5) and (2, 1).
The equation of the line that passes through these points is found in the following way:
![y = mx + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/fc4cgm6covys37zv2opmmp9ps4jxyjepvh.png)
Where
m = slope
![m = \frac {y_2-y_1}{x_2-x_1}\\\\m = (1-5)/(2-0)\\\\m = -2\\\\b = y_2-mx_2\\\\b = 1 -(-2)(2)\\\\b = 5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/stiy4etvd8c77nijz25q99elkui0ne68h5.png)
So
![y = -2x + 5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/df3pgx3fkennjgf4bcqz8eain4thv8lxhp.png)
We must apply to this function the transformation
.
We know that a transformation of the form
shifts the graph of the function f(x) h units to the right if
, or shifts the function f(x) h units towards the left if
.
In this case
then the transformation
displaces the graph 4 units to the right.
Therefore if f(x) passes through the points (0,5) and (2,1) then
passes through the points (4, 5) (6, 1)
And its equation is:
![y = -2(x-4) +5\\\\y = -2x +13](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2bs0w1iodzpdp1rynzwboxjbffecpf1836.png)
Observe the attached image