Question

A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. Calculate the specific heat capacity of iron.

Answer 1

0.46 J/gC

Step-by-step explanation:

The specific heat capacity of a material is given by:

where

Q is the amount of heat absorbed

m is the mass

is the variation of temperature

For the piece of iron in the problem:

Substituting into the equation,

Step-by-step explanation:

Answer 2

0.46 J/gC

Step-by-step explanation:

The specific heat capacity of a material is given by:

`C_s = (Q)/(m \Delta T)`

where

Q is the amount of heat absorbed

m is the mass

`\Delta T` is the variation of temperature

For the piece of iron in the problem:

`m = 15.75 g`

`Q=1086.75 J`

`\Delta T=175 C-25 C=150^(\circ)`

Substituting into the equation,

`C_s = (1086.75 J)/((15.75 g)(150^(\circ)C))=0.46 J/gC`