Answer:
This relationship is a function
Explanation:
By definition a relation is defined as a function if and only if for each input value x there is only one output value y.
In this case we observe the following ordered pairs
(0.2), (1.2), (2.2) (3.2)
We see that each value x has only a value of y.
![x = 0,\ y = 2\\\\x = 1,\ y = 2\\\\x = 2,\ y = 2\\\\x = 3,\ y = 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jjkq23taxkf72rqnrx8d54i3hxt4vup2e5.png)
Therefore this relationship is a function