Answer:
One mass's kinetic energy is 4 times the other.
Explanation:
The formula for kinetic energy is
![KE=(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qm3oiu3t5knkt2lzxpgz8n1rhs06ibh22e.png)
Where
KE is the kinetic energy
m is the mass
v is the velocity
- Now, let mass of the first be m (second is identical so mass of 2nd is m as well)
- Let velocity of the first one be v. Since 2nd one is travelling twice as fast, its velocity will be 2v
KE of 1st mass is:
![(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/physics/middle-school/21jx8l4rmwqqnf7exy7nilgxwywxn5ljpc.png)
KE of 2nd mass is:
![(1)/(2)m(2v)^2\\=(1)/(2)m(4v^2)\\=(1)/(2)mv^2 * 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/idykst1dgkx3ycdxblxr8pnt0orulg6f1e.png)
Hence, the kinetic energy of the 2nd mass is 4 times the first.