We want to find a fraction that is between
![(1)/(4)\:and\:(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t7xx9is3rphs0s3cknv6flllvp27j8cuvn.png)
There are several ways to go about this.
There are also infinitely many fractions that can be found between the given fractions.
Let us go for the one in the middle of the two fractions.
So we add the two fractions and divide by 2.
a)
![((1)/(4) +(1)/(2) )/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5x3yict33hs7xh3t8bwuh6ti73q3rfdilk.png)
Find LCM for the numerator
![((1+2)/(4))/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wgfgt5z0f06rh6rur83utn49weq3va6y2t.png)
Simplify:
![((3)/(4))/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vvejzmdne9bu11zk6m4ay8up73adf5phpk.png)
![((3)/(2))/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xg3je8azf472qi33s25quozsw8tweo96ug.png)
![(3)/(8)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h6yzj811cvaco0yx9yz04pg6gvpbbtajt1.png)
b)
![((1)/(3) +(3)/(4) )/(2)=(13)/(24)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/30r5sp0a33dyih8cuiedyhbleycaf8s1ji.png)
c)
![((1)/(2) +(3)/(4) )/(2)=(5)/(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o4q7izndzgao9nrsweyh2abx7wafiboczi.png)
d)
![((3)/(5) +(7)/(8) )/(2)=(59)/(80)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9fceqnykywr1mlihbe46k90jqjbhhpfv9e.png)