Answer:
Third graph.
Explanation:
Given system of inequalities,
x + y ≥ 4
2x + 3y < 12
Graphing x + y ≥ 4 :
Related equation of inequality x + y ≥ 4 is x + y = 4,
Having x-intercept = (4, 0)
y-intercept = (0,4),
'≥' shows the solid line,
0 + 0 ≥ 4 ( false )
⇒ The region of inequality x + y ≥ 4 is above the line.
Graphing 2x + 3y < 12 :
Related equation of inequality 2x + 3y < 12 is 2x + 3y = 12,
Having x-intercept = (6, 0)
y-intercept = (0,4),
'<' shows the dotted line,
2(0) + 3(0) < 12 ( true )
⇒ The region of inequality 2x + 3y < 12 is below the line.
Hence, only third graph satisfies the above conditions.
Third graph is correct.