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For each pair of numbers, find a third whole number such that the three numbers form a pythagorean triple.

33,55
42,58
60,65

User Alya
by
8.4k points

1 Answer

1 vote

Answer:

Part 1) The third whole number is 44

Part 2) The third whole number is 40

Part 3) The third whole number is 25

Explanation:

we know that

The Pythagoras theorem states that

In a right triangle


c^(2) =a^(2) +b^(2)

where

c is the greater length side

a and b are the legs

Case 1) we have

33,55

step a

Let


a=33, b=55

Find the value of c


c^(2) =a^(2) +b^(2)


c^(2) =33^(2) +55^(2)


c^(2) =4,114


c =64.14 ------> is not a whole number

step b

Let


a=33, c=55

Find the value of b


b^(2) =c^(2) -a^(2)


b^(2) =55^(2) -33^(2)


b^(2) =1,936


b=44

Case 2) we have

42,58

step a

Let


a=42, b=58

Find the value of c


c^(2) =a^(2) +b^(2)


c^(2) =42^(2) +58^(2)


c^(2) =5,128


c =71.61 ------> is not a whole number

step b

Let


a=42, c=58

Find the value of b


b^(2) =c^(2) -a^(2)


b^(2) =58^(2) -42^(2)


b^(2) =1,600


b=40

Case 3) we have

60,65

step a

Let


a=60, b=65

Find the value of c


c^(2) =a^(2) +b^(2)


c^(2) =60^(2) +65^(2)


c^(2) =7,825


c =88.46 ------> is not a whole number

step b

Let


a=60, c=65

Find the value of b


b^(2) =c^(2) -a^(2)


b^(2) =65^(2) -60^(2)


b^(2) =625


b=25

User Nir Hartmann
by
8.4k points