Answer:
Part 1) The value of b is
![12\ units](https://img.qammunity.org/2020/formulas/mathematics/high-school/af682gdf7th720fr60s0uud6o1tsvyzz2t.png)
Part 2)
![tan(22.6\°)=(a)/(12)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jn061hdkisg7vmhtauf5l244a1kekhj17c.png)
Explanation:
Part 1)
Find the value of b
In the right triangle ABC
Let
b-------> the adjacent side to angle 22.6°
a -----> the opposite side to angle 22.6°
13 ----> the hypotenuse of the right triangle ABC
we have
The cosine of angle 22.6° is equal to divide the adjacent side to angle 22.6° by the hypotenuse
![cos(22.6\°)=(b)/(13)](https://img.qammunity.org/2020/formulas/mathematics/high-school/wjjebbre6qk2yhp32c5plecvl17bypnbhu.png)
Solve for b
Multiply both sides by 13
![b=(13)cos(22.6\°)=12\ units](https://img.qammunity.org/2020/formulas/mathematics/high-school/gf1z5xd4mgbtw0kxj4khudcwte3qlot92s.png)
Part 2) Which equation correctly uses the value of b to solve for a?
we know that
In the right triangle ABC
The tangent of angle 22.6° is equal to divide the opposite side to angle 22.6° by the adjacent side to angle 22.6°
so
![tan(22.6\°)=(a)/(b)](https://img.qammunity.org/2020/formulas/mathematics/high-school/m7vyatfnvhsrbaa2fh458nqwc6om7t0ff6.png)
we have
![b=12\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f6pmfv227sn1dw15giveqmnfx9190smj7u.png)
substitute
![tan(22.6\°)=(a)/(12)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jn061hdkisg7vmhtauf5l244a1kekhj17c.png)