Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?

Question

asked Jul 14, 2020 231k views

2 Answers

Cmonkey · Answer 1 · 2020-07-18T12:12:21+0000

For this case we have the following quadratic equation:

0 = -3x ^ 2-2x + 6

Where:

$a = -3\\b = -2\\c = 6$

The quadratic formula, to find the roots, is given by:
$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Substituting the values:

$x = \frac {- (- 2) \pm \sqrt {(- 2) ^ 2-4 (-3) (6)}} {2 (-3)}\\x = \frac {2 \pm \sqrt {(- 2) ^ 2 + 4 (3) (6)}} {2 (-3)}$

Answer:

$x = \frac {2 \pm \sqrt {(- 2) ^ 2 + 4 (3) (6)}} {2 (-3)}$