Question

There are 8 players on a tennis team. The team is planning to play in a doubles tournament. How many different groups of players of 2 players can the coach make, if the position does not matter?

28
64
20,160
40,320

Answer 1

The coach can make 28 different groups of players of 2 players for the doubles tournament.

Step-by-step explanation:

The coach needs to select 2 players out of 8 for the doubles tournament. Since the order in which the players are selected does not matter, we can use the combination formula. The number of different groups of 2 players that the coach can make is given by the formula:

C(n, r) = n! / (r! * (n-r)!)

where n is the total number of players and r is the number of players to be selected. Plugging in the values, we have:

C(8, 2) = 8! / (2! * (8-2)!) = 8! / (2! * 6!) = (8 * 7 * 6!) / (2! * 6!) = (8 * 7) / (2 * 1) = 28

Therefore, the coach can make 28 different groups of players of 2 players.

Answer 2

The answer is 28!!!

Step-by-step explanation:

Use the combinations formula:

`C = (n!)/(r!(n-r)!)`

n = 8

r = 2

`C = (8!)/(2!~*~6! ) = 28\\`

I got it right! Look at the pic for proof.

Hope this helps!! :)