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If 19000 is borrowed for 10 years at 3.25% interest compound annually if the loan is paid I full at the end of the period how much must be paid back

User DotMorten
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\bf ~~~~~~ \textit{Compound Interest Earned Amount}


\bf A=P\left(1+(r)/(n)\right)^(nt) \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$19000\\ r=rate\to 3.25\%\to (3.25)/(100)\dotfill &0.0325\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &10 \end{cases} \\\\\\ A=19000\left(1+(0.0325)/(1)\right)^(1\cdot 10)\implies A=19000(1.0325)^(10)\implies A\approx 26160.99

User Dinshaw Raje
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