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What is the domain and range of the square root of x+3-1?

User Gyasi
by
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1 Answer

6 votes

Answer:


\large\boxed{\text{The domain:}\ x\geq-3\to x\in[-3,\ \infty)}\\\boxed{\text{The range:}\ y\geq-1\to y\in[-1,\ \infty)}

Explanation:


y=√(x+3)-1\\\\The\ domain:\\\\x+3\geq0\qquad\text{subtract 3 from both sides}\\\\x\geq-3\to x\in[-3,\ \infty)\\\\The\ range:\\\\√(x+3)\geq0\qquad\text{subtract 1 from both sides}\\\\√(x+3)-1\geq-1\\\\y\geq-1\to y\in[-1,\ \infty)

User Yun Luo
by
6.3k points
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