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Evaluate the difference quotient for the function f(x)=-8x+1

1 Answer

5 votes

Answer:

-8.

Explanation:

The difference quotient for ax^n = anx^(n-1) so here we have

Difference quotient of -8x + 1

= -8x(1-1) + 0 (the difference quotient of any constant is 0).

= -8x^0

= -8 * 1

= -8 (answer).

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