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What is the range of the function f(x) = x^2 + 2 when the domain is (-1, 0, 1)?​

User Bobbles
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1 Answer

5 votes

Answer:

The range: {2, 3}

Explanation:

We have the function:


f(x)=x^2+2

The domain:


x\in\{-1,\ 0,\ 1\}

The range:

put the values of , and calculate the value of f(x):

for x = -1:


f(-1)=(-1)^2+2=1+2=3

for x = 0:


f(0)=0^2+2=0+2=2

for x = 1:


f(1)=1^2+2=1+2=3


y\in\{2,\ 3\}

User Boxxar
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