Question

Select the point that satisfies y<=-x+3, y<=x^2-3x

Answer 1

(1, -2)

Explanation:

We have the two equations:

y ≤ -x + 3 (1)

y ≤ x^2 - 3x → Factorizing → y ≤ x(x-3) (2)

So the two equations are:

y ≤ x(x-3)

y ≥ (x-3)

Solving the system of equations:

y=x(x-3)

y = (x-3)

Then: x(x-3) = (x-3). Solving for 'x' we have that x=1.

If x=1, then y= -2

The point thay satisfies the inequations is:

(1, -2)