Given x varies inversely with y and xy = 2, what is the value of x when y = 1?

Question

asked Jan 25, 2020 150k views

2 Answers

GuilhE · Answer 1 · 2020-01-31T17:12:27+0000

Answer:

Explanation:

The equation for inverse variation is:

x=(k)/(y)

Where "k" is the constant of variation.

If you solve for for the constant "k", you get the form:

k=xy

So, if
xy=2 then
k=2

Knowing the value of "k", you can find the value of "x" when
y=1 , by substituting these values into the equation
x=(k)/(y) .

Therefore, you get that the value of "x" when
y=1 is:

$x=(2)/(1)\\\\x=2$