What’s the equation of a circle with a center -3,4 and radius 1

Question

asked Dec 13, 2020 40.2k views

1 Answer

Kuujo · Answer 1 · 2020-12-17T03:59:34+0000

Answer:

(x+3)^2 + (y-4)^2 = 1

Explanation:

Equation of a circle can be found by

(x-a)^2 + (y-b)^2 = r^2

Given center 3,-4 i.e

a= 3 and b=-4

and radius r = 1

Putting the values of a,b and r in the equation we get:

$(x-(-3))^2 + (y-4)^2 =(1)^2\\(x+3)^2 + (y-4)^2 = 1$