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What’s the equation of a circle with a center -3,4 and radius 1

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Answer:


(x+3)^2 + (y-4)^2 = 1

Explanation:

Equation of a circle can be found by


(x-a)^2 + (y-b)^2 = r^2

Given center 3,-4 i.e

a= 3 and b=-4

and radius r = 1

Putting the values of a,b and r in the equation we get:


(x-(-3))^2 + (y-4)^2 =(1)^2\\(x+3)^2 + (y-4)^2 = 1

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