Answer:
![y=3sec\left((1)/(2)x\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3mi00tgz2lnisll4thqnpz68ppj84a65jw.png)
Explanation:
The graphs of
can be obtained from the graph of the cosine function using the reciprocal identity, so:
![sec(x)=(1)/(cos(x))](https://img.qammunity.org/2020/formulas/mathematics/high-school/hskan4njwkipi3w8agodmu4jj7nj1v6rie.png)
But in this problem, the graph stands for the function:
![y=3sec\left((1)/(2)x\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3mi00tgz2lnisll4thqnpz68ppj84a65jw.png)
Because the period is now 4π as indicated and for
in the figure and this can be proven as follows:
![Period=(2\pi)/((1)/(2))=4\pi](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aapmsosy4sk1jr7ha7ar9mxp3uvu7i5pdu.png)
Also,
as indicated in the figure and this can be proven as:
![y=3sec\left((1)/(2)x\right) \\ \\ y=(3)/(cos(0.5x)) \\ \\ y=(3)/(cos(0.5(0))) \\ \\ y=(3)/(1)=3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c8yenypd5p8e6sglj8kr11l7iw5ejui0i2.png)