Answer: d) 4/9, 4/9, 1/9
Explanation:
Let's look at all of the possible combinations of 1st spin & 2nd spin:
AA BA CA
AB BB CB
AC BC CC
P (X=0): how many times is A not in the combination? 4 out of 9
P (X=1): how many times is A in the combination once? 4 out of 9
P (X=2): how many times is A in the combination twice? 1 out of 9