Question

If y varies directly as x and y = 8 when x = 4, what is the value of y when x = 16?

Answer 1

y is 32 when x has the value 16

Explanation:

The equation governing this relationship has the form y = kx.

Replacing y with 8 and x with 4, we get 8 = 4k, so that k = 2 is the constant of proportionality.

Then y = 2x. When x = 16, y = 2(16) = 32.

y is 32 when x has the value 16.

Answer 2

32

Explanation:

because when x=4 it became x=16 by multiplying by 4 so if you multiply 8 from y=8 by 4 it becomes 32