Question

Can someone please help me with this!!! pleasee

Answer 1

`\large\boxed{Q6.\ \sin X\approx0.778}\\\boxed{Q7.\ x\approx5.9}`

Explanation:

Q6.

`\sin\theta=(opposite)/(hypotenuse)`

We have

`opposite=14\\\\hypotenuse=18`

Substitute:

`\sin X=(14)/(18)=(14:2)/(18:2)=(7)/(9)=0.777...\approx0.778`

Q7.

Use sine.

We have

`opposite=x\\\\hypotenuse=8\\\\\alpha=48^o\\\\\sin48^o\approx0.7431`

Substitute:

`(x)/(8)=0.7431` multiply both sides by 8

`x=5.9448\to x\approx5.9`