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What is the concentration of the acid in this titration 1.2 m 2.4 m 1.95 m 0.98 m 1.98 m

What is the concentration of the acid in this titration 1.2 m 2.4 m 1.95 m 0.98 m-example-1

2 Answers

3 votes

Answer:

1.95

Step-by-step explanation:

Just did the test and it was correct!

User SidK
by
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2 votes

Answer: The correct answer is 1.95 M

Step-by-step explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:


n_1M_1V_1=n_2M_2V_2

where,


n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of unknown acid which is HCl.


n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is
Ca(OH)_2

We are given:


n_1=1\\M_1=?M\\V_1=(45.5-0.0)=45.5mL\\n_2=2\\M_2=1.2M\\V_2=(37.5-0.5)=37mL

Putting values in above equation, we get:


1* M_1* 45.5=2* 1.2* 37\\\\M_1=1.95M

Hence, the concentration of unknown HCl solution comes out to be 1.95 M.

User MaxHeap
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