Question

Find the gravitational potential at a point on the earth surface. Take mass as of earth as 5.98×10^24kg,it's radius as6.38×10^6nand G=6.67×10^-11Nm^2kg^-2​

Answer 1

`-6.25\cdot 10^7 J`

Step-by-step explanation:

The gravitational potential at a point on the Earth surface is given by:

`U=-(GM)/(R^2)`

where

G=6.67×10^-11Nm^2kg^-2 is the gravitational constant

M=5.98×10^24kg is the Earth's mass

R=6.38×10^6 m is the Earth's radius

Substituting the numbers into the equation, we find

`U=-((6.67\cdot 10^(-11))(5.98\cdot 10^(24)))/((6.38\cdot 10^6))=-6.25\cdot 10^7 J`