Question

How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?

Answer 1

Answer: 9.57 mol

Explanation:1.1=8.7L/(C12H22O11)

multiply each side by 8.7.

=9.57mol

Answer 2

9.57 mol.

Step-by-step explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (no. of moles of sucrose)/(V of the solution (L)).

1.1 M = (no. of moles of sucrose)/(8.7 L).

∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.