Question

(4Q) What is the amplitude and period of f(t)= -2cos (3t)

Answer 1

d. The amplitude is 2

period:

`(2\pi)/(3)`

Step-by-step explanation

The given function is

`f(t) = - 2 \cos(3t)`

This function is of the form,

f(t) = a cos(bt)

The amplitude of this function is |a|

where a=-2

`| - 2| = 2`

The period of this function is given by,

`T= (2\pi)/(b)`

But b=3,

`T= (2\pi)/(3)`

Option D is correct.