2 Answers

Lejahmie · Answer 1 · 2020-06-05T01:54:20+0000

Answer:

The standard deviation is 4.05 to the nearest hundredth

.Explanation:

The standard deviation is given by:

$s=\sqrt{(\sum(x-\bar X)^2)/(n) }$

The mean,
$\bar X=9$

This implies that;

$s=\sqrt{((4-9)^2+(5-9)^2+(10-9)^2+(11-9)^2+(15-9)^2)/(5) }$

$s=\sqrt{(25+16+1+4+36)/(5) }$

$s=\sqrt{(82)/(5) }=4.049691$

Hence the standard deviation is 4.05 to the nearest hundredth.

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