Hey need help asap! Can you please find the ending solution to this y=(x+2)^2+2 y=x+6 i came up with this for x, x^2+3x=0 and x(x+3)=0 i just need the ones for y and to know the ending solution.

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asked Oct 23, 2020 143k views

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Hey need help asap! Can you please find the ending solution to this

y=(x+2)^2+2
y=x+6
i came up with this for x, x^2+3x=0 and x(x+3)=0 i just need the ones for y and to know the ending solution.

Mathematics
middle-school

Madhukar asked

by Madhukar

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1 Answer

5 votes

Answer:

y = x2+3

Explanation:

Mohammad Arif answered Oct 30, 2020

by Mohammad Arif

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