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HELPPPPPPPPP i have the most trouble with math what’s the answer??

HELPPPPPPPPP i have the most trouble with math what’s the answer??-example-1

2 Answers

3 votes

Answer:


√(13)-√(11)

Explanation:

When we have an expression in this form:


(a)/(√(x)+√(y)  )

We need to multiply it by
(√(x)-√(y)  )/(√(x)-√(y))

Let's do this:


(2)/(√(13)+√(11)  )*(√(13)-√(11))/(√(13)-√(11))\\=(2(√(13)-√(11)))/((√(13)+√(11))(√(13)-√(11)))\\=(2√(13) -2√(11) )/((√(13) )^2-(√(11) )^2)\\=(2√(13) -2√(11) )/(13-11)\\=(2√(13) -2√(11) )/(2)\\=(2(√(13) -√(11) ))/(2)\\=√(13)-√(11)

Note: we used the property
√(a) √(a) =a

User Sisanared
by
8.1k points
4 votes

Answer:

Last Option


√(13) -√(11)

Explanation:

To simplify the expression you must multiply the numerator and the denominator of the fraction by the conjugate of the denominator.

If you have an expression of the form


a +b then its conjugate will be
a - b.

The result of that multiplication will be


a ^ 2 -b ^ 2

Therefore we have the expression


(2)/(√(13) +√(11))

By multiplying by the conjugate of the denominator we have


(2)/(√(13) +√(11))*(√(13) -√(11))/(√(13) -√(11))\\\\\\(2(√(13) -√(11)))/((√(13))^2 -(√(11))^2)\\\\\\(2√(13) -2√(11))/(13 -11)\\\\\\(2√(13) -2√(11))/(2)


=√(13) -√(11)

User Justin Pihony
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