Question

find the length of the second base of a trapezoid with one base measuring 8 inches, a height of 13 inches, and an area of 149.5 square inches ​

Answer 1

The length of the second base is
`15\ in`

Explanation:

we know that

The area of a trapezoid is equal to

`A=(1)/(2)(b1+b2)h`

where

b1 is the length of the first base

b2 is the length of the second base

h is the height of the trapezoid

In this problem we have

`b1=8\ in`

`h=13\ in`

`A=149.5\ in^(2)`

substitute and solve for b2

`149.5=(1)/(2)(8+b2)(13)`

`299=(8+b2)(13)`

`299/13=(8+b2)`

`(8+b2)=23`

`b2=23-8=15\ in`