Answer:
What is the expected value when rolling a fair 12-sided die?
132=6.5
Recall the definition of the expected value:
E[X]=∑ni=1xp(x)
Here, we have 12 possible values the die can take on, and the probability of each one is the same: 1/12. So we can just pull the term p(x), the probability of each outcome, out of the summation:
E[X]=112∑12i=1x
A useful trick here is that the sum of the numbers 1..N=N(N+1)2. So:
E[X]=11212(13)2
E[X]=12(13)12(2)
E[X]=132
Explanation:
hope it helps you :)