Question

N2+ 3 H2 -> 2 NH3 If 12.0 g of H2 reacts with excess N2. then what mass of NH3 will be produced?

Answer 1

To find the mass of NH3 produced, use stoichiometry and the molar masses of H2 and NH3. The mass of NH3 produced is 9.33 g.

Step-by-step explanation:

In order to determine the mass of NH3 produced, we need to use stoichiometry.

From the balanced equation, we can see that for every 3 moles of H2, we produce 2 moles of NH3.

Using the molar mass of H2 (2 g/mol) and NH3 (17 g/mol), we can set up a proportion to find the mass of NH3 produced.

12.0 g H2 * (2 mol NH3 / 3 mol H2) * (17 g NH3 / 1 mol NH3) = 9.33 g NH3