Question

An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of the electric force on this electron due to this field?

1.6 × 10-3 newtons

1.4 × 1024 newtons

2.2 × 10-14 newtons

7.4 × 10-13 newtons

4.5 × 1014 newtons

Answer 1

Option (c) - 2.2 × 10-14 newtons

(a) for Plato users!

Answer 2

2.2 × 10-14 newtons

Step-by-step explanation:

The electric force exerted on a charged particle is given by

`F=qE`

where we have in this case:

`q=-1.6\cdot 10^(-19)C` is the charge of the electron

`E=1.4\cdot 10^5 N/C` is the strength of the electric field

Since we are only interested in the magnitude of the electric force, we can neglect the negative sign of the charge; therefore, the strength of the electric force is

`F=(1.6\cdot 10^(-19)C)(1.4\cdot 10^5 N/C)=2.2\cdot 10^(-14) N`