Question

Write an equation of the line that is perpendicular to -x + y = 5 and passes through the point (2, -5).

Answer 1

Convert to y = mx + b

y = x + 5

The slope is one

Now, convert this into point slope form:

y - y1 = m(x - x1)

y + 5 = 1 (x - 2)

y + 5 = x - 2

Subtract 5 from both sides.

y = x - 7

An equation of the line that is perpendicular to -x + y = 5 and passes through the point (2, -5) should be y = x - 7

Answer 2

Equation of the line is y =-1x - 3

Explanation:

an equation of the line that is perpendicular to -x + y = 5 and passes through the point (2, -5).

-x + y = 5, solve for y to find the slope of the given line

add x on both sides

y=x+5, slope of given line = 1

Slope of perpendicular line is the negative reciprocal of the slope of given line

slope of perpendicular line = -1

m = -1 and passes through point (2,-5) is (x1,y1)

use point slope formula

y - y1= m(x-x1)

y + 5 = -1(x-2)

y+5 = -1x +2

Subtract 5 from both sides

y = -1x-3

Equation of the line is y =-1x - 3