Question

What is the [OH-] if the [H3O+] is 1 x 10 -6?

Answer 1

The answer is [OH⁻] = 1 x 10⁻⁸.

To find OH⁻, divide the ionic product of water by [H₃O⁺] as :

OH⁻ + H₃O⁺ = H₂O

• [OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
• [OH⁻] = 1 x 10⁻⁸