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If f(x)=x^3-x, what is the average rate of change of f(x) over the interval [1,5]?

User Necreaux
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1 Answer

6 votes

Answer:

30

Explanation:

Average rate of change=Δf(x)/Δx = [f(x2)-f(x1]/[x2-x1]

Δf(x)/Δx = [f(5)-f(1]/[5-1]

f(5)=5³-5=120

f(1)=1³-1=0

Δf(x)/Δx = [120-0]/[5-1]=120/4=30

User Megan
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