Answer:
= 6.7 × 10^-6 M
Step-by-step explanation:
The number of moles of AgCl
= 0.0012 g/143.32 g/mol
= 8.373 × 10^-6 Moles
Concentration or Molarity = moles × volume
800 grams = 800 cm³ = 0.8 L
= 8.373 × 10^-6 Moles × 0.8 L
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