Question

Help pleaseeeee !!!!

Write an equation of a line that passes through the points (-3,2) and (-7,10)

An explanation too would be very much appreciated !! :)))))

Answer 1

`\large\boxed{y-2=-2(x+3)}`

Explanation:

The point-slop form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

`m=(y_2-y_1)/(x_2-x_1)`

We have the points (-3, 2) and (-7, 10). Substitute:

`m=(10-2)/(-7-(-3))=(8)/(-4)=-2\\\\y-2=-2(x-(-3))\\\\y-2=-2(x+3)`