Question

Find the range for the function k(n) = 2n^2 when D = {–2, 1, 3}.

Thanks a lota if you answer!

Answer 1

R = { 8, 2, 18}

Explanation:

The range of the function is the set of function values or y-values. To find them, substitute the values x = -2, 1, and 3 into the function.

k(n) = 2n^2

k(-2) = 2(-2)^2

k(-2) = 2(4) = 8

k(n) = 2n^2

k(1) = 2(1)^2

k(1) = 2(1) = 2

k(n) = 2n^2

k(3) = 2(3)^2

k(3) = 2(9) = 18

The range is R = { 8, 2, 18}.