Question

Someone please help me with this.

Answer 1

The solution is (-2,-11)

Explanation:

The given system is ;

`(1+y)/(2y) -(3x+1)/(y) =0, y\\e0`

Multiply through by 2y.

`1+y-2(3x+1)=0`

Expand;

`1+y-6x-2=0`

`y-6x=1`

`y=6x+1...(1)`

Also we have;

`(2y+8)/(12x+10)+(4x)/(y+7)=3...(2)`

Put equation (1) into (2)

`(2(6x+1)+8)/(12x+10)+(4x)/(6x+1+7)=3`

`(12x+2+8)/(12x+10)+(4x)/(6x+1+7)=3`

`(12x+10)/(12x+10)+(4x)/(6x+8)=3`

`(12x+10)/(12x+10)+(4x)/(6x+8)=3` for
`x\\e -(5)/(6),x\\e -(4)/(3)`

`1+(4x)/(6x+8)=3`

`(4x)/(6x+8)=3-1`

`(4x)/(6x+8)=2`

Cross multiply;

`4x=2(6x+8)`

`4x=12x+16`

`4x-12x=16`

`-8x=16`

Divide through by -8.

x=-2

Put x=-2 into equation (1).

y=6(-2)+1

y=-11

The solution is (-2,-11)