ANSWER
![y = {x}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uop7if1okcndr5ky124acapm62lerawchi.png)
Step-by-step explanation
For a function to be an invertible, it must be a one-to-one function.
In other words , it's graph should pass the horizontal line test.
It is obvious that,
![y = x](https://img.qammunity.org/2020/formulas/mathematics/high-school/gy1e9rweepurcokz29u8tnph7dovyhzcqo.png)
and
![y = 2x + 1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4nvv4uykzo0ho4irff8yun8tit162xwba6.png)
will pass the horizontal line test.
But
![y = {x}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uop7if1okcndr5ky124acapm62lerawchi.png)
has a v-shape and hence cannot pass the horizontal line test.
This means that y=x² is not invertible. That is, its inverse is not a function.
Let us quickly check that:
![y = {x}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uop7if1okcndr5ky124acapm62lerawchi.png)
Interchange x and y.
![x = {y}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/68jf7txasvvnubweekdxsgpseefwcit2x5.png)
Solve for y,
![y = \pm \: √(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2vrmi4di4bigcolifp1oza1nw8kibrhe9r.png)
This is not a function, because it doesn't pass the vertical line test.