Question

How would i solve A & B?

Answer 1

`\large\boxed{a)\ A\approx93.53\ in^2}\\\boxed{b)\ 8,640\ in^2}`

Explanation:

a)

The formula of an area of a regular hexagon:

`A=6\cdot(a^2\sqrt3)/(4)`

a - side length

We have a = 6in. Substitute:

`A=6\!\!\!\!\diagup^3\cdot(6^2\sqrt3)/(4\!\!\!\!\diagup_2)=3\cdot(36\!\!\!\!\!\diagup^(18)\sqrt3)/(2\!\!\!\!\diagup_1)=3\cdot18\sqrt3=54\sqrt3\ in^2\\\\A\approx93.53\ in^2`

b)

`5ft=5(12in)=60in\\\\12ft=(12)(12in)=144in`

The area of a hallway:

`A=(60)(144)=8,640\ in^2`