Question

Find the difference. (4x 2 - 6x + 8) - (3x 2 - 6x + 2)

x^2 + 6
7x^2 - 12x - 6
x^2 + 12x + 6
x^2 - 12x - 6

Answer 1

A. x^2 + 6

Explanation:

(4x^2 - 6x + 8) - (3x^2 - 6x + 2) =

The first set of parentheses is unnecessary, so just remove it.

= 4x^2 - 6x + 8 - (3x^2 - 6x + 2)

To remove the second set of parentheses, change the sign of each term inside.

= 4x^2 - 6x + 8 - 3x^2 + 6x - 2

Now combine like terms.

= x^2 + 6

Answer 2

For this case we must find the difference of the following polynomials:

`(4x ^ 2-6x + 8) - (3x ^ 2-6x + 2) =`

Taking into account that:

`- * - = +\\+ * - = -`

We have:

`4x ^ 2-6x + 8-3x ^ 2 + 6x-2 =\\x ^ 2 + 0x + 6 =\\x ^ 2 + 6`

Answer:

`x ^ 2 + 6`