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Which function can be used to represent the graphed geometric sequence?

f(x) = 80(
(1)/(4) x^(x-1))
f(x) = 320(
(1)/(4) x^x-1
f(x) = 80(4)x – 1
f(x) = 320(4)x – 1

2 Answers

4 votes

Answer:

its A trust me coz i dont have the time to explain rn

User Andrey Lebedenko
by
4.9k points
5 votes

Answer:

f(x) = 80(1/4 x^x-1) ⇒ first answer

Explanation:

* Lets explain the geometric sequence

- In the geometric progression there is a constant ratio between

each two consecutive numbers

Ex:

5 , 10 , 20 , 40 , 80 , ………………………. (×2)

5000 , 1000 , 200 , 40 , …………………………(÷5)

* General term (nth term) of a Geometric Progression:

- U1 = a , U2 = ar , U3 = ar2 , U4 = ar3 , U5 = ar4

Un = a(r)^n-1, where a is the first term , r is the constant ratio

between each two consecutive terms and n is the position of

the number in the sequence

* In the problem we have 4 answers we will search which one can

be put in the form a(r)^n-1

- The first answer is 80(1/4 r^x-1)

∵ We can multiply 80 by 1/4 ⇒ 80 × 1/4 = 20

∴ It will be 20(x^x-1) ⇒ the form of the geometric sequence

* The answer is the first answer

User Graeme Blackwood
by
4.7k points