Question

What is the factorization of g3 – 125? (g– 5)(g2 + 5g + 10) (g – 25)(g2 + 25g + 625) (g – 5)(g2 + 5g + 25) (g – 25)(g2 + 5g + 125)

Answer 1

g – 1 – 5/g+1

Explanation:

Answer 2

(g - 5)(g² + 5g + 25)

Explanation:

g³ - 125 is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b² )

here a = g and b = 5, that is

g³ - 125 = g³ - 5³ = (g - 5)(g² + 5g + 25)